What is the probably of getting the follow events? - hens invitations
If the probability of a partridge is 0.58 and the probability of a pear tree is 0.76, and these are independent events, find the probability of a partridge and a pear tree.
If the probability of a female turtle is 0.53, dove, the probability of at least one female turtle in the pair.
If the probability that a hen is true that French nationality is 0.81, the probability of exactly two of the three French hens
If the probability that a bird is called, is in fact 0.63, you can find the probability that the bird was the first in the third attempt.
If the probability that a real gold ring is 0.72, you can find the probability of three or fewer on five golden rings.
If the probability of a real chicken egg is 0.83, what is the probability of a goose with a fourth on or before the test.
If the probability of a swan 0.23 Drowning is the probability that exactly 4 of the 7 swans drown.
If the probability of obtaining a good acid-a-milking, 0.38,Find the expected number of girls is an acid-milking in the group of the 8th
If the probability of a dancer 0.18 to accept an invitation to the dance, you will find the expected number of women applying for prior to adoption.
If the probability that a man jumps blade is 0.24, what the probability of obtaining their first jump, Mr lame after the sixth attempt.
If the probability of frozen pipes is 0.63, determine the probability of 8 or more frozen pipes eleven.
If the probability of a dropping drummer is 0.48, so the standard deviation found twelve drummers drumming drums leaking drums.
If you should provide the answers to three significant digits, the sum of twelve responses 14.0479.
Sunday, January 10, 2010
Hens Invitations What Is The Probably Of Getting The Follow Events?
2 comments:
I want an answer for you ... is better, if only after one or two questions by e-mail, and not all ... Nobody has time to answer 12 questions about!
Anyway ...
For the first, if are independent, which means that the result does not rely on other results. To the probability that both find true, simply multiply:
(.58) * (.76) = .441
For the 2nd to find "at least find" that the probability that then subtract, 1 Since the probability of women .53, which means that the probability of 'is female' .47. To do this twice per second, just multiply:
(.47) * (.47) = .221
This is the probability that none of them are women. Thus, the probability that at least is a woman who is the 1 - (, 221) = 779
That's all I have time for. Good luck with the rest!
I want an answer for you ... is better, if only after one or two questions by e-mail, and not all ... Nobody has time to answer 12 questions about!
Anyway ...
For the first, if are independent, which means that the result does not rely on other results. To the probability that both find true, simply multiply:
(.58) * (.76) = .441
For the 2nd to find "at least find" that the probability that then subtract, 1 Since the probability of women .53, which means that the probability of 'is female' .47. To do this twice per second, just multiply:
(.47) * (.47) = .221
This is the probability that none of them are women. Thus, the probability that at least is a woman who is the 1 - (, 221) = 779
That's all I have time for. Good luck with the rest!
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